Question

Question number 40 please find​

Answer 1

Given Equation :-

5√5 x² + 20x + 3√5 = 0

By Splitting the middle term , we have

5√5 x² + 15x + 5x + 3√5 = 0

5x(x√5 + 3) + √5(x√5 + 3) = 0

(5x + √5)(x√5 + 3) = 0

So here , Zeros of the given Equation are :-

5x + √5 = 0

5x = -√5

x = -√5/5

also

x√5 + 3 = 0

x√5 = -3

x = -3/√5 => -3√5/5

Hope it helped you...