question number 7 and 8
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hey 8 is very simple
cosec^2¢ -1=cot^2¢[a^2-b^2=(a+b)(a-b)
so (cesec¢+1)(cosec¢-1)=cot^2¢
put this value in question
we get 1+ [(cosec¢+1)(cosec¢-1)]/(cosec¢+1)
=1+cosec¢-1=cosec¢
in (ii) pu the value of tan^2¢=sec^2¢-1
you get your answer ....
cosec^2¢ -1=cot^2¢[a^2-b^2=(a+b)(a-b)
so (cesec¢+1)(cosec¢-1)=cot^2¢
put this value in question
we get 1+ [(cosec¢+1)(cosec¢-1)]/(cosec¢+1)
=1+cosec¢-1=cosec¢
in (ii) pu the value of tan^2¢=sec^2¢-1
you get your answer ....
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