question of jee mains
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this is your jee mains look its a question
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-9/2
Explanation:
v = 3sin(x + pi/2)
differentiating wrt t,
a = 3cos(x+pi/2). dx/dt
dx/dt = v
therefore a = 9sin(x + pi/2)cos(x + pi/2)
putting x = pi/4
we get a = -9/2
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