Question

Question p (2)= 3 (x) + 2 (×) + (×) +0 (×) +15 (×)+ 0 +5

Answer 1

We have to put 2 as the value of x in the equation. We get p(2)=3x2+2x2+2+0+15x2+0+5
So p(2)=6+4+2+0+30+0+5
We get p(2)=47

Answer 2

the question should be x(2)
x(2)= 3 (x) + 2 (×) + (×) +0 (×) +15 (×)+ 0 +5
⇒3*2+2*2+2+0*2+15*2+0+5
⇒6+4+2+0+30+0+5
⇒47