question. p(y)=y2 -y +1
Answer. p(y)=y2-y+1
p(0)=(0)2-0+1=1
p(1)=(1)2-1+1=1-1+1=1
p(2)=(2)2-2+1=4-2+1=3
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sorry I don't know
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what is your exact question?
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