Question text In the given figure, rays OA, OB, OC and OD are such that angle AOB = 56 degrees, angle BOC = 100 degrees, angle COD = x degrees, and angle DOA = 74 degrees. Find the value of x (Hint - sum of angles around a point is 360 degrees)
Answers
Answered by
4
Answer:
We know that,
Sum of all angles around a point is 360
o
.
Therefore,
100
o
+56
o
+74
o
+x=360
o
x=130
o
Answered by
5
Answer:
Given :
OA,OB,OC and OD are such that angle AOB= 56° angle BOC=100°,angle COD=x° and angle DOA = 74°
To find :
Value of x
Solution :
sum of all the angles around a point is 360°
=> ∠AOB + ∠BOC + ∠COD + ∠DOA = 360°
=> 56° + 100° + x + 74 = 360°
=> 156 + x + 74 = 360°
=> 230° + x = 360°
=> x = 360° - 230°
=> x = 130°
=> ∠COD = 130°
Sum other formula's :
Volume of cylinder = πr²h
T.S.A of cylinder = 2πrh + 2πr²
Volume of cone = ⅓ πr²h
C.S.A of cone = πrl
T.S.A of cone = πrl + πr²
Volume of cuboid = l × b × h
C.S.A of cuboid = 2(l + b)h
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