Question

QUESTION
The sum of three consecutive multiples of 11 is 363. What are these multiples.?​

Answer 1

Answer:

110, 121 and 132 are the consecutive multiples of 11 whose sun is 363

Answer 2

Answer:

let 11x, 11(x-1), 11(x+1) be three consecutive multiple of 11. such that 11(x-1)+ 11x+11(x+1)=363

11[x-1+x+x+1]=363

11(3x)=363

3x=363/11=33

x=33/3=11

therefore three multiple are : 11x-11=110,11x=121 and 11x+11=132

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