Question

"Question16
Evaluate, sin30°/cos45° + cot45°/sec60° - sin60°/tan45° - cos30°/sin90°
Chapter6,T-Ratios of particular angles Exercise -6 ,Page number 288"

Answer 1

Hey there!
We know that,
sin30 = 1/2
cos45 = 1/√2
cot45 =1
sec60 = 2
sin60 = √3/2
tan45 = 1
cos30 = √3/2
sin90 = 1 .

sin30°/cos45° + cot45°/sec60° - sin60°/tan45° - cos30°/sin90°

= 1/2 ( 1/√2 ) + 1 / ( 2 ) - (√3/2 ) / ( 1 ) - (√3/2 ) / 1

= (√2 / 2 )+ 1/2+ ( - √3/2 ) - ( √3/2 )

= [√2/2 + 1/2 - 2√3] /2

= [√2 + 1 - 2√3 ]/2

=[ 1 + √2 - 2√3 ] / 2

Hope helped!

Answer 2

HELLO DEAR,


we know that:-

sin30° = 1/2
cos45° = 1/√2
cot45° = 1
sec60° = 2
sin60° = √3/2
tan45° = 1
cos30° = √3/2
sin90° = 1


now put this values in Equation,

sin30°/cos45° + cot45°/sec60° - sin60°/tan45° - cos30°/sin90°

we get,


(1/2) / (1/√2) + 1/2 - (√3/2)/1 - (√3/2)/1

= 1/√2 + 1/2 - √3/2 - √3/2

= 1/√2 + (1 - 2√3)/2

= (2 + √2 - 2√6)/2√2

= (√2 + 1 - 2√3)/2



I HOPE ITS HELP YOU DEAR,
THANKS