"Question26
If A = 30° , Verify that : cos 2A = 1- tan²A / 1 + tan²A
Chapter6,T-Ratios of particular angles Exercise -6 ,Page number 289"
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Answered by
12
HELLO DEAR,
GIVEN THAT:-
A = 30°
NOW,
cos (2*30°) = cos60°
= cos60°
= 1/2
NOW,
(1 - tan²A)/(1 + tan²A)
= (1 - tan²30°)/(1 + tan²30°)
= (1 - 1/3) / ( 1 + 1/3)
= [(3 - 1)/3] / [ (3 + 1)/3]
= (2/3) / (4/3)
= 2/3 * 3/4
= 1/2
hence , verified
I HOPE ITS HELP YOU DEAR,
THANKS
GIVEN THAT:-
A = 30°
NOW,
cos (2*30°) = cos60°
= cos60°
= 1/2
NOW,
(1 - tan²A)/(1 + tan²A)
= (1 - tan²30°)/(1 + tan²30°)
= (1 - 1/3) / ( 1 + 1/3)
= [(3 - 1)/3] / [ (3 + 1)/3]
= (2/3) / (4/3)
= 2/3 * 3/4
= 1/2
hence , verified
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
4
Hey there!
Given to verify : cos 2A = 1- tan²A / 1 + tan²A
If A = 30°
1) cos 2A = cos (2*30) = cos60 = 1/2 [ T - Ratio of 60° , π/3 ]
2) tanA = tan30 = 1/√3
Now,
Given equation to verify : cos 2A = 1- tan²A / 1 + tan²A
==================================
Finding the value of cos2A
= cos60
= 1/2
==================================
Finding the value of 1 - tan²A / 1 + tan²A
= 1 - tan²30 / 1 +tan²30
= 1 - (1/√3)² / 1 + (1/√3)²
= 1 - 1/3 / ( 1 + 1/3 )
= (2/3) / (4/3)
= 2/3 * 3/4
= 1/2
==================================
Here, We observe that cos 2A = 1- tan²A / 1 + tan²A
Hence proved that, cos 2A = 1- tan²A / 1 + tan²A for A = 30°
Given to verify : cos 2A = 1- tan²A / 1 + tan²A
If A = 30°
1) cos 2A = cos (2*30) = cos60 = 1/2 [ T - Ratio of 60° , π/3 ]
2) tanA = tan30 = 1/√3
Now,
Given equation to verify : cos 2A = 1- tan²A / 1 + tan²A
==================================
Finding the value of cos2A
= cos60
= 1/2
==================================
Finding the value of 1 - tan²A / 1 + tan²A
= 1 - tan²30 / 1 +tan²30
= 1 - (1/√3)² / 1 + (1/√3)²
= 1 - 1/3 / ( 1 + 1/3 )
= (2/3) / (4/3)
= 2/3 * 3/4
= 1/2
==================================
Here, We observe that cos 2A = 1- tan²A / 1 + tan²A
Hence proved that, cos 2A = 1- tan²A / 1 + tan²A for A = 30°
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