Question

Question3. Find the current drawn from the battery by the network of four resistors Shown in the figure.​

Answer 1

$\large\underline\mathfrak\red{Answer \: :- }$

• $\bf{R_1 = 10 ohm}$
• $\bf{R_2 = 10ohm }</li><li>$
• $\bf{R_3 = 10ohm }</li><li>$
• $\bf{R_4= 10ohm }</li><li>$

$\large\underline\mathfrak\red{To \: find \: :- }$

• Current

$\large\underline\mathfrak\red{Solution \: :- }$

Equivalent resistance the given network is

$\bf{ \frac{1}{R} = \frac{1}{R_4} + \frac{1}{R_1 + R_2 + R_3} }$

$\bf{ = \frac{1}{10} + \frac{1}{10 + 10 + 10} = \frac{1}{10} + \frac{1}{30} }$

$\bf{ = \frac{3 + 1}{30} = \frac{4}{30} }$

$\bf{\therefore \: R = \frac{30}{4} = 7.5Ω}$

Current drawn from the battery

$\bf{I= \frac{V}{R} = \frac{3}{7.5} = \frac{30}{75} = \frac{2}{5} }$

$\bf\implies{I = 0.4 A }$

$\boxed{\bf{\red{Current = 0.4 A}}}$