Math, asked by tetsuyahanamaki, 8 days ago

questions did he answer correctly? A sum of 500 is in the form of denominations of 5 and 10. If the total number of notes is 90 find the number of notes of each denomination.​

Answers

Answered by gauravkanyalclass6a
0

Answer:

Let us assume the number of 5 rupees note be 'x'. Then the number of 10 rupees note will be '90-x' (Total number of notes=90)

The total amount is 500. So according to the question:

5x+10(90-x)=500

5x+900–10x=500

-5x=500–900

-5x=—400

X=—400/—5 (Since, — and — = +)

X=400/5

X=80

Hence, according to our solution:—

Number of 5 rupees note=X that is 80

And number of 10 rupees note=(90-x) that is (90–80)=10

Therefore, there are 80 five rupees note and 10 ten rupees note..

Step-by-step explanation:

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Answered by AnshulDhomne
0

Step-by-step explanation:

Let us assume the number of 5 rupees note be 'x'. Then the number of 10 rupees note will be '90-x' (Total number of notes=90) The total amount is 500. So according to the question: 5x+10(90-x)=500 5x+900–10x=500 -5x=500–900 -5x=—400 X=—400/—5 (Since, — and — = +) X=400/5 X=80 Hence, according to our solution…

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