Math, asked by sohan41, 1 year ago

questions no. 17.....

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Answered by guptakhushbu1995

LHS =SecA=1/cosA
1+1/COSA /1/COSA
COSA+1/cosA/1/cosA
CosA+1/cosA ×cosA
CosA+1 /1 ×cosA-1/cosA-1
Cos^2A-1/cosA-1. (Cos^2A-1=sin^2A)
Sin^2A/cosA-1

sohan41: ???

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