Math, asked by sohan41, 1 year ago

questions no. 17.....

Attachments:

Answers

Answered by guptakhushbu1995
1

LHS =SecA=1/cosA
1+1/COSA /1/COSA
COSA+1/cosA/1/cosA
CosA+1/cosA ×cosA
CosA+1 /1 ×cosA-1/cosA-1
Cos^2A-1/cosA-1. (Cos^2A-1=sin^2A)
Sin^2A/cosA-1


sohan41: ???
Similar questions