Question

Questions no.5 please it's urgent

Answer 1

this is the answer. I hope this would help u

Answer 2

Given ∠PCA = 110° and PC is the tangent.

Given O is the centre of the circle.

Hence points A, O, B and P all lie on the same line.

Join points C and O.  

∠BCA = 90° [Since angle in a semi circle is 90°]

Also ∠OCP = 90° [Since radius ⊥ tangent]

From the figure we have, ∠PCA =∠PCO + ∠OCA

That is, 110° = 90° + ∠OCA

Therefore, ∠OCA =20°

In ΔAOC, AO = OC [Radii]

So, ∠OCA = ∠OAC =20°

In ΔABC, we have

∠BCA = 90°, ∠CAB = 20°

Therefore, ∠CBA = 70°