Math, asked by prakhart892, 4 months ago

questions
 {7}^{2x + 3}    = 1

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Answered by Anonymous
1

Answer:

7^2x+3 = 1

7^2x+3 = 1[We know a^0 = 1]

7^2x+3 = 1[We know a^0 = 1]So , we can write →

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0[ a^m = a^n , then m=n]

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0[ a^m = a^n , then m=n]or, 2x+3 = 0

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0[ a^m = a^n , then m=n]or, 2x+3 = 0or, 2x = -3

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0[ a^m = a^n , then m=n]or, 2x+3 = 0or, 2x = -3or, x = -3/2

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0[ a^m = a^n , then m=n]or, 2x+3 = 0or, 2x = -3or, x = -3/2Answer → Value of x = -3/2.

7^2x+3 = 1[We know a^0 = 1]So , we can write →7^2x+3 = 1×7^0or, 7^2x+3 = 7^0[ a^m = a^n , then m=n]or, 2x+3 = 0or, 2x = -3or, x = -3/2Answer → Value of x = -3/2.______________

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@darksoul

Answered by dhrubayanpal7a32020
0

Step-by-step explanation:

I think it helps you a lot

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