Question

QUETION:-
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1.80 g of a certain metal burnt in oxygen gave 3.0 g of its oxide. 1.50 g of the same metal heated in steam gave 2.50 g of its oxide. Show that these results illustrate the law of constant proportion.

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Answer 1

Given :

• 1.80 g of a certain metal burnt in oxygen gave 3.0 gm of its oxide.
• 1.50 g of the same metal heated in steam gave 2.50 gm of its oxide.

To Prove :

Show that these results illustrate the law of constant proportion.

Required Solution :

Case ① :

In the first case of the oxide,

→ Weight of metal = 1.80 gm

→ Weight of oxygen = (3.0 - 1.80)

→ Weight of oxygen = 1.2 gm

$\tt{:\implies \dfrac{Weight \:of \:metal}{Weight \:of \:oxygen}}$

$\tt{:\implies \cancel{\dfrac{1.80}{1.5}}}$

$\bf{:\implies \underline{ \: \: \underline{ \red{ \: \: 1.5 \: \: }} \: \: }}$

Case ② :

In the second case of the oxide,

→ Weight of metal = 1.50 gm

→ Weight of oxygen = 2.5 - 1.50

→ Weight of oxygen = 1 gm

$\tt{:\implies \dfrac{Weight \:of \:metal}{Weight \:of \:oxygen}}$

$\tt{:\implies \cancel{\dfrac{1.50}{1}}}$

$\bf{:\implies \underline{ \: \: \underline{ \red{ \: \: 1.5 \: \: }} \: \: }}$

Thus, in both cases of the oxide the proportions of the weights of the metal and oxygen are fixed so this results follow the law of constant proportion.

Hence Proved !

Answer 2

ɢɪᴠᴇɴ-:

• 1.80 g of a certain metal burnt in oxygen gave 3.0 gm of its oxide.
• 1.50 g of the same metal heated in steam gave 2.50 gm of its oxide.

ғɪɴᴅ-:

Show that these results illustrate the law of constant proportion.

$Solution$

1.50 g of the same metal heated in steam gave 2.50 g of its oxide. ... Thus, in both samples of the oxide the proportions of the weights of the metal and oxygen are fixed. Hence, the results follows the law of constant proportion.

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