Quick lime, CaO, is obtained by burning of limestone, CaCO3, in a lime kiln and the reaction is represented as; CaCO3------- CaO + CO2 . what weight of limestone must be heated to obtain 112 kgs of quick lime?
Answers
Answered by
1
Step One
========
Find the amount of limestone present in grams..
95% of 2000 kg = 1900 kg Limestone
1 kg = 1000 grams
1900 kg = 1000 * 1900 = 1900000 grams
Step Two
=======
Determine the Equation.
Ca CO3 ===> CaO + CO2
Step Three
========
Determine the number of moles of limestone.
1 mole of lime stone =
Ca = 40
C = 12
O3 = 3 * 16 = 48
! mole of limestone = 40 + 12 + 48 = 100 grams / mole
1 mole Lime stone = 100 grams
x mole Lime stone = 1900000
100x = 1900000
x = 19000 moles
Step 4
======
determine the weight of CaO
1 mole CaO = 40 + 16 = 56 grams / mole
19000 mole CaO = x
x = 19000 * 56 = 1064000 grams or
x = 1064 kg
Answered by
0
first find out molecular weight...
molecular wt of cao = 40+ 16 = 56 molecular wt of caco3 = 40 +12+16×4 1 =100 grams
now..consider the reaction....
CaCO3 --- CaO +CO2
so in this reaction all atoms are balanced...then...we conclude that..
1 mole of cao reacts with 1 mole of caco3
112/56 = weight of caco3/100
2×100 =weight of caco3
so weight of limestone required= 200gm
...ans
molecular wt of cao = 40+ 16 = 56 molecular wt of caco3 = 40 +12+16×4 1 =100 grams
now..consider the reaction....
CaCO3 --- CaO +CO2
so in this reaction all atoms are balanced...then...we conclude that..
1 mole of cao reacts with 1 mole of caco3
112/56 = weight of caco3/100
2×100 =weight of caco3
so weight of limestone required= 200gm
...ans
Similar questions