Question

Quiz 9/30 Salaries of Rupa and Meeta are in the ratio 4:5 and total to 1,80,000. By how much is Rupa's salary less than Meeta's?​

Answer 1

Given :

Ratio of salaries : 4:5

Total salary of both friends : ₹180000

To find :

The money of Meeta more than Rupa.

Solution :

First, we should find the salaries of Rupa and Meeta.

Let the salary of Rupa be 4x.

Let the salary of Meera be 5x.

According to the question,

$\sf \dashrightarrow 4 : 5 = 180000$

$\sf \dashrightarrow 4x : 5x = 180000$

$\sf \dashrightarrow 4x + 5x = 180000$

$\sf \dashrightarrow 9x = 180000$

$\sf \dashrightarrow x = \dfrac{180000}{9}$

$\sf \dashrightarrow x = 20000$

Now, let's find the salaries of Rupa and Meeta.

Salary of Rupa :

$\sf \dashrightarrow 4x = 4(20000)$

$\dashrightarrow$₹$\sf 80000$

Salary of Meeta :

$\sf \dashrightarrow 5x = 5(20000)$

$\dashrightarrow$₹$\sf 100000$

Now, let's find the answer of this question.

$\sf \dashrightarrow Meeta's \: salary - Rupa's \: salary$

$\sf \dashrightarrow 100000 - 80000$

$\dashrightarrow$₹$\sf 20000$

Hence, Meeta have ₹20000 more than Rupa.

Answer 2

Answer:

Rupa 's salary is ₹20,000 less than Meeta's.

Step-by-step explanation:

Given :

Ratios of the salary of Rupa and Meeta = 4:5

Total of Rupa and Meeta 's Salary = ₹1,80,000

To be Calculated :

Amount by which Rupa's salary is less than Meeta's

Calculations:

It is given that the ratios of the salaries of Rupa and Meeta is 4:5 , So,

Let us assume that Rupa's Salary is ₹4x and Meeta 's Salary is ₹5x .

Now, According to the question,

$4x \: + 5x \: = 180000 \\ 9x = 180000 \\ x = \frac{180000}{9} \\ x = 20000$

Now, Calculating the salaries of Meeta and Rupa, we have :

Salary of Meeta= 5x = ₹ 5 ×20,000= ₹1,00,000

Salary of Rupa= 4x = ₹4 × 20,000 = ₹ 80,000

Hence, the salaries of Meeta and Rupa are ₹1,00,000 and ₹ 80,000 respectively.

Now, Calculating the amount by which Rupa's salary is less than Meeta's.

Therefore, difference = ₹ 1,00,000-₹ 80,000 = ₹ 20,000.

Hence, Rupa 's salary is ₹20,000 less than Meeta's.

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