Qus.13: A circular well of radius 3.5 m dug 20 m deep and the earth so dug is spread on a rectangular plot of length 14 m and breadth 11 m. Find :
1. Volume of the earth dug out.
2. Height of the platform formed by spreading the earth on the rectangular plot.
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Volume of earth dugout=pi*r*r*depth
=769.69m^3
Volume of rectangular plot =length *breadth*height
=14*11*h
Since the dugout soil is spread on the rectangular plot the volume of plot is equal to volume of soil dugout
769.96=14*11*h
h=4.997988m
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