Question

Qus. U. Equation (x² + 1)² – 0x² = 0
cas has four real roots (6) Has two real roots
(C) No real roots
( (a) Has one real soots.​

Answer 1

Answer:

no real root as in this x² value should be -1

Answer 2

Answer:

no real roots

Step-by-step explanation:

$(x^{2} + 1)^{2} - 0x^{2} = (x^{2} + 1)^{2} = 0\\x^{2} + 1 = 0^{2}$

⇒ $x^{2}$ = -1

hence there are no real roots