Question

Quwlestion no. 05
The last one..

Answer 1

hope this helps you.....

Answer 2

Density of
Water = d₁ = 1 g/cm³
Body = d₂
Liquid = d₃
Volume of body = V

Buoyant Force = Volume of water displaced × Density of water × g
= (80 / 100)Vd₁g ……[∵ 80% of body is in water]
= 0.8Vg

Weight of body = Volume of body × Density of body × g
= Vd₂g

Body in water is in equilibrium
Buoyancing Force = Weight of body
0.8Vg = Vd₂g
d₂ = 0.8 g/cm³

When body placed in liquid of density d₃
Specific density = Density of liquid / Density of water
5 = d₃ / (1 g/cm³)
d₃ = 5 g/cm³

Buoyancing Force due to liquid = Volume of liquid displaced × Density of liquid × g
= V’d₃g
= 5V’g

Weight of body = mg = Vd₂g = 0.8Vg

Body is in equilibrium
Buoyancing Force due to liquid = Weight of body
5V’g = 0.8Vg
V’ = 0.16V

Percentage of volume inside liquid = 0.16 × 100 = 16%
Percentage of Volume outside liquid = 100 - 16 = 84%