Question

π(r+132)^2 - πr^2 = 14190
Please help me solve this equation step by step. It will really be a big help for my previous question.​

Answer 1

$\pi(r+132)^2 - \pi r^2 = 14190\\\pi(r^2+264r+17424)-\pi r^2=14190\\\pi(r^2+264r+17424-r^2)=14190\\264r+17424=\dfrac{14190}{\pi}\\\\264r=\dfrac{14190}{\pi}-17424\\\\264r=\dfrac{14190}{\pi}-\dfrac{17424\pi}{\pi}\\\\264r=\dfrac{14190-17424\pi}{\pi}\\\\r=\dfrac{14190-17424\pi}{264\pi}\\\\r= \dfrac{215}{4\pi}-66$

Answer 2

Step-by-step explanation:

π{(r+132)^2-r^2}=14190

I{(r+132-r)(r+132+r)}=14190

22/7{(132)(132+2r)=14190

132(132+2r)=645×7

44(132+2r)=215

calculate and solve it