Question

R. Calculate the boss of sulfur dioxide
produced by bumag 16 g of sulfar in
excess of oxygen in contact process.
Average comic mass : S = 32
0=160)
(Ans. 329)​

Answer 1

Answer:

The mass of sulfer dioxide is 48unit

Explanation:

S+O2=SO2

1mole of sulfer and 1mole of oxygen reacts and make one mole of sulfer dioxide.

As given ¦ s=32unit o=16unit

Therefore, the atomic mass of SO2=32+(16*2)=64unit

now if we say that we will use 16gram of sulfer

then the atomic. mass of SO2=16+(16*2)=48unit

thanks