Physics, asked by thapliyalkajal15, 1 month ago

r is a distance of a point from the centre of a short dipole, then the electric field intensity due to the short dipole remains proportional to
a) r^2
b) r^3
c) r^-4
d) r^-3​

Answers

Answered by reevachauhan18
8

Explanation:

hope this helps you

mark me as brainlist

Attachments:
Answered by rambabu083155
2

Answer:

Electric field intensity due to short dipole remains proportional to r^{-3}

Explanation:

The electric field intensity due to an electric dipole is given by:

E = \frac{1}{4\pi e_{0} } \frac{2p}{r^{3} }

where, p = dipole moment

e_{0} = electrical permitivity of free space

r = distance from dipole

It is clear that,

E ∝ \frac{1}{r^{3} }

so, r = -3

hence this is the required solution.

Similar questions