Question

R1=40 ohm , R2=20 ohm, R3=10 ohm , Rp=?​

Answer 1

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Answer 2

$\sf \frac{1}{ R_p } = \frac{1}{ \: R_1} + \frac{1}{ \: R_2} + \frac{1}{ \: R_3}$

so ,

$\sf \frac{1}{ R_p }= \frac{1}{4 0} + \frac{1}{20} + \frac{1}{10} = \frac{1 + 2 + 4}{40} = \frac{7}{4 0}$

so ,

$\boxed{ \sf\R_p = \: \frac{40}{7} \: Ω}$