Question

R7 Find the sum of AP 1, 3, 5, 7
... up to 12 terms.​

Answer 1

Answer:

144

Step-by-step explanation:

Sum of 12 terms= (n/2)(2a+(n-1) d)

= 12/2(2*1+(12-1)*2)

= 6*(2+11*2)

=6*(2+22)

=6*(24)

=144