Science, asked by diya617, 5 months ago

राइट ए लेटर टू द प्रिंसिपल कमिश्नर ऑफ़ योर एरिया प्वाइंट इन ही मोर अबाउट हाउ द प्लांस इन कंडोमिनियम यार एरिया अलसो मेंशन द इंपैक्ट ऑफ टू द प्रेसिडेंट भजन एनिमल दो​

Answers

Answered by shreenath13
1

राइट ए लेटर टू द प्रिंसिपल कमिश्नर ऑफ़ योर एरिया प्वाइंट इन ही मोर अबाउट हाउ द प्लांस इन कंडोमिनियम यार एरिया अलसो मेंशन द इंपैक्ट ऑफ टू द प्रेसिडेंट भजन एनिमल दो

ANSWER

Motion of the particle is shown above.

Let the total distance covered by the particle be s.

For second half motion :

Distance covered x+y=

2

s

.....(1)

Equal interval of time is taken to cover x and y distances with speed v

1

and v

2

, respectively.

v

ANSWER

Motion of the particle is shown above.

Let the total distance covered by the particle be s.

For second half motion :

Distance covered x+y=

2

s

.....(1)

Equal interval of time is taken to cover x and y distances with speed v

1

and v

2

, respectively.

v

1

x

=

v

2

y

⇒xv

2

=yv

1

⇒(

2

s

−y)v

2

=yv

1

(using 1)

2

s

v

2

=y(v

1

+v

2

)

⇒y=

2(v

1

+v

2

)

sv

2

From (1), we get x+

2(v

1

+v

2

)

sv

2

=

2

s

⇒x=

2(v

1

+v

2

)

sv

1

Time taken to cover second half motion, t=

v

1

x

+

v

2

y

=

(v

1

+v

2

)

s

Time taken to cover first half motion, t

=

u

s/2

=

2u

s

Now average velocity V

avg

=

Totaltime

Totaldistance

∴ V

avg

=

2u

s

+

(v

1

+v

2

)

s

s

⟹ V

avg

=

v

1

+v

2

+2u

2u(v

1

+v

2

)

solution

1

x

=

v

2

y

⇒xv

2

=yv

1

⇒(

2

s

−y)v

2

=yv

1

(using 1)

2

s

v

2

=y(v

1

+v

2

)

⇒y=

2(v

1

+v

2

)

sv

2

From (1), we get x+

2(v

1

+v

2

)

sv

2

=

2

s

⇒x=

2(v

1

+v

2

)

sv

1

Time taken to cover second half motion, t=

v

1

x

+

v

2

y

=

(v

1

+v

2

)

s

Time taken to cover first half motion, t

=

u

s/2

=

2u

s

Now average velocity V

avg

=

Totaltime

Totaldistance

∴ V

avg

=

2u

s

+

(v

1

+v

2

)

s

s

⟹ V

avg

=

v

1

+v

2

+2u

2u(v

1

+v

please don't forget to make me a brainlist and I

)

solution

Attachments:
Similar questions