Question

Rachana borrowed a certain sum at the rate of 15% per annum. If she paid at the end of two years Rs. 1290 as interest compounded annually, find the sum she borrowed.​

Answer 1

$\huge\bf\red{Given :-}$

$\bf \blue{Rate = 15 percent\: per\: annum}$

$\bf \blue {Time = 2 years}$

$\bf \blue{CI = Rs 1290}$

$\huge\bf\red{To \:Find :-}$

$\bf \green{The\: sum \:she \:borrowed}$

$\huge\bf\red{Solution :-}$

$\Large {\underline{\boxed{\pink{CI = P [(1 + \dfrac{R}{100})n – 1]}}}}$

$\bf \purple{1290 = P [(1 + \dfrac{15}{100})2 – 1] }$

$\bf\purple{1290 = P [0.3225] }$

$\bf \purple{P = \dfrac{1290}{0.3225} } \\ \bf \red{RS.4000}$

${\underline{\boxed{\green{∴ The \:sum\: is\: Rs .4000}}}}$

Answer 2

Step-by-step explanation:

Given =

Rate = 15% p.a

time. : 2yrs

c.i. : rs1290

so answer

r×t\100

15×2/100

30/100

3.7

3.7/1290

123.67

ans: 123.67

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