Math, asked by Anonymous, 10 months ago

Rachel an engineering student was asked to make a model shaped like a cylinder with two cones attached at its two ends by using a thin aluminium sheet the diameter of the model is 3 cm and its length is 12 Cm if each cone has a height of 2 centimetre find the volume of air contained in the model that Rachel made​

Answers

Answered by kaushikumarpatel
10

Answer:

Radius of the model (cylinder and cone) = 1.5 cm

Length of model = 12 cm

Height of the cone = 2 cm

Therefore, the height of the cylinder = 12 - 2 - 2 = 8 cm

Volume of model = Volume of cylinder + Volume of 2 cones

(Assumption : π = 22 / 7 )

                             = π r^2 h + 1 / 3 π r^2 h * 2

                             = π r^2 (h + 2 / 3 h)

                             = 22 / 7 * 1.5 * 1.5 (8 + 2 / 3 * 2)

                             = 22 / 7 * 1.5 * 1.5 (28 / 3)

                             = 22 * 3

                             = 66 cm^3

HOPE THAT IT WAS HELPFUL!!!!

MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!

Answered by BrainlyKingdom
0

Volume of Air Contained in Model

= Volume of Model

= Volume of Cylinder + Volume of 1st cone + Volume of 2nd Cone

= πr²h + 1/3πr²h + 1/3πr²h

= (π × r² × h) + (1/3 × π × r² × h) + (1/3 × π × r² × h)

= (22/7 × (3/2)² × h) + (1/3 × 22/7 × (3/2)² × h) + (1/3 × 22/7 × (3/2)² × h)

= (22/7 × 9/4 × h) + (1/3 × 22/7 × 9/4 × 2) + (1/3 × 22/7 × 9/4 × h)

= (198/28 × h) + (22/217 × 9/4 × h) + (22/21 × 9/4 × h)

= (198/28 × (12 - 4)) + (22/21 × 9/4 × 2) + (22/21 × 9/4 × 2)

= (198/28 × 8) + (22/21 × 9/4 × 2) + (22/21 × 9/4 × 2)

= (198/28 × 8) + (22/21 × 9/2 × 1) + (22/21 × 9/2 × 1)

= (198/28 × 8) + (22/21 × 9/2) +  (22/21 × 9/2)

= (1584/28) + (198/42) + (198/42)

= (56.57) + (4.71)  + (4.71)

= 65.99 cm³

≈ 66 cm³

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