Rachel an engineering student was asked to make a model shaped like a cylinder with two cones attached at its two ends by using a thin aluminium sheet the diameter of the model is 3 cm and its length is 12 Cm if each cone has a height of 2 centimetre find the volume of air contained in the model that Rachel made
Answers
Answer:
Radius of the model (cylinder and cone) = 1.5 cm
Length of model = 12 cm
Height of the cone = 2 cm
Therefore, the height of the cylinder = 12 - 2 - 2 = 8 cm
Volume of model = Volume of cylinder + Volume of 2 cones
(Assumption : π = 22 / 7 )
= π r^2 h + 1 / 3 π r^2 h * 2
= π r^2 (h + 2 / 3 h)
= 22 / 7 * 1.5 * 1.5 (8 + 2 / 3 * 2)
= 22 / 7 * 1.5 * 1.5 (28 / 3)
= 22 * 3
= 66 cm^3
HOPE THAT IT WAS HELPFUL!!!!
MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!
Volume of Air Contained in Model
= Volume of Model
= Volume of Cylinder + Volume of 1st cone + Volume of 2nd Cone
= πr²h + 1/3πr²h + 1/3πr²h
= (π × r² × h) + (1/3 × π × r² × h) + (1/3 × π × r² × h)
= (22/7 × (3/2)² × h) + (1/3 × 22/7 × (3/2)² × h) + (1/3 × 22/7 × (3/2)² × h)
= (22/7 × 9/4 × h) + (1/3 × 22/7 × 9/4 × 2) + (1/3 × 22/7 × 9/4 × h)
= (198/28 × h) + (22/217 × 9/4 × h) + (22/21 × 9/4 × h)
= (198/28 × (12 - 4)) + (22/21 × 9/4 × 2) + (22/21 × 9/4 × 2)
= (198/28 × 8) + (22/21 × 9/4 × 2) + (22/21 × 9/4 × 2)
= (198/28 × 8) + (22/21 × 9/2 × 1) + (22/21 × 9/2 × 1)
= (198/28 × 8) + (22/21 × 9/2) + (22/21 × 9/2)
= (1584/28) + (198/42) + (198/42)
= (56.57) + (4.71) + (4.71)
= 65.99 cm³
≈ 66 cm³