Question

Rachel plays a game by rolling two number cubes with sides numbered 1 through 6. To win the game, the sum of the numbers facing up must be 11. What is the probability that Rachel will win the game?

A. P(sum of 11)=2/6
B. P(sum of 11)=2/12
C. P(sum of 11)=2/36
D. P(sum of 11)=4/36

Answer 1

Probability

Solution:

• The sample space when two cubes are rolled is S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

• Now the sample space in favour of 'sum 11' is A = {(5, 6), (6, 5)}

• So the probability of getting 'sum 11' is P (A) = n (A) / n (S) = 2/36

• ∴ the probability of winning the game is 2/36.

• Option C is correct.

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Answer 2

Answer:

Step-by-step explanation:

2/36 is the probability 1/18 simplified