Question

racing car has a uniform acceleration of 4 metre per second square what distance will it cover in 10 seconds after start

Answer 1

s= ut + 1/2 at2
u=0 as at time the car is at rest...
s= 1/2at2= 1/2*(4)*(10)^2= 200m

Answer 2

Answer :

Given,

Initial velocity (u) = 0

Acceleration (a) = 4 ms^-2

Time (t) = 10 s

→ We can solve this sum with two methods.

✤ First Method :

→ Using first equation of motion :

❖ $\sf{v = u + at}$

= $\sf{0 + 40}$

= $\fbox{\sf v = 40 m/s}$

→ Using third equation of motion :

❖ $\sf{2as = v^2 - u^2}$

= $\sf{2(4) s = 1600}$

= $\large\sf{s = \frac{1600}{8}}$

= $\large\fbox{\sf s = 200\:m}$

✤ Second Method :

→ Using second equation of motion :

❖ $\sf{s = ut + \frac{1}{2} at^2}$

= $\sf{0 \times 10 + \frac{1}{2} (4) (10)^2}$

= $\large\fbox{\sf s = 200\:m}$

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