Question

racing car has a uniform acceleration of 74 metre per second square what distance will it cover in 10 seconds after start​

Answer 1

$s = ut + \frac{1}{2} {at}^{2} \\ \\ = 0 \times 10 + (\frac{1}{2} \times 74 \times 10 \times 10) \\ \\ = 0+ 37 \times 100 \\ \\ = 3700m$

Hence, The covered distance will be 3 km 700 m.

Answer 2

Answer:u=0

a=74m/s2

t= 10 sec

By using second eq.

S= ut + 1/2 at2

S= 0×10 + 1/2×74×10×10

S= 3700 m

Explanation: