racing car has uniform acceleration of 40 per second square with distance will it cover 10 seconds after the start
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Answered by
2
hey dear
here is your answer
given data :
initial velocity (u) = 0
time (t) = 10 seconds
acceleration (a) = 40 m/s²
now, to find = distance
solution :
by using 2nd equation of motion
s = ut+1/2at²
s = 0*10+1/2*40*(10)²
s = 0+20*100
s = 2000 meter
hope it helps :)
here is your answer
given data :
initial velocity (u) = 0
time (t) = 10 seconds
acceleration (a) = 40 m/s²
now, to find = distance
solution :
by using 2nd equation of motion
s = ut+1/2at²
s = 0*10+1/2*40*(10)²
s = 0+20*100
s = 2000 meter
hope it helps :)
Answered by
2
let distance is 's'
by formula
s = ut + 1/2at²
s = 0(10) + 1/2×40×(10)²
s = 2000m
distance cover = 2000meter
hope it helps you
@di
by formula
s = ut + 1/2at²
s = 0(10) + 1/2×40×(10)²
s = 2000m
distance cover = 2000meter
hope it helps you
@di
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