radhika daily goes for morning walk on a particular street.onthe first day,she walks a distance of 500m and then she uniformily increases the distance covered in each day by 60m.on which day will she walk a distance of 3km 140m?
Answers
Answered by
2
A=500
D=60
An=3140
An=A+(n-1)D
3140=500+(n-1)60
2640=(n-1)60
44=n-1
n=45
Therefore
On the 45th day Radhika walks 3km 140m
D=60
An=3140
An=A+(n-1)D
3140=500+(n-1)60
2640=(n-1)60
44=n-1
n=45
Therefore
On the 45th day Radhika walks 3km 140m
Answered by
1
Step-by-step explanation:
here's your answer..hope it helps...
she will walk 3km 140 m on the 45th day..
Attachments:
Similar questions
Social Sciences,
5 months ago
English,
5 months ago
Math,
5 months ago
Math,
10 months ago
Biology,
10 months ago
Physics,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago