Question

Radhika says that "(x-2)(X+1)=(x-1)(X+3)"is a quadratic equation.justify your answer.​

Answer 1

(x-2)(X+1)=(x-1)(X+3)

step 1

${x}^{2} + 1x - 2x - 2 = {x}^{2} + 3x - x - 3$

step 2

${x}^{2} - 2x - 2 = {x}^{2} + 2x - 3$

step 3

${x}^{2} - {x}^{2} - 2x - 2x = - 3 + 2$

step 4

$- 4x = - 1 \\ x = \frac{1}{4}$

In step 3 all the ${x}^{2}$ terms get cancelled and the highest power in the equation is 1

so it is not a quadratic equation

Radhika is wrong