Question

· Radiation from a mercury lamp source is of energy 2.845 eV. Calculate the wavelength
of the radiation
a) 579.0 nm
b) 355.0 nm c) 404.7nm d) 435.9 nm
longth of an electron with a kinetic energy of 1.00 eV.
Determine thed
D​

Answer 1

Step-by-step explanation:

Given Radiation from a mercury lamp source is of energy 2.845 eV. Calculate the wave length of the radiation

• Now energy of a photon depends on the wavelength.
•                       So E = hν
•                               = h c / λ
• We need to find the wavelength and 1eV = 1.6 x 10^-19 Jave  
• So we have λ = hc / E (h is planck’s constant, c is speed of light)
•                      = 6.626 x 10^-34  x 2.998 x 10^8 / 2.845 x 1.6 x 10^-19
•                     =  0.436.9 x 10^-9
•                     = 435.9 nm

Reference link will be

https://brainly.in/question/8799309

Answer 2

Answer:

435.9 is the right ans mate...........