Question

Radiation of wavelength lambda is incident on a photocell.the fastest emitted electron has a speed v.if the wavelength is vhanged to 3lambda/4,the sleed of the fastest emitted electron will be
A)>v(4/3)^1/2
B) C)=v(4/3)^1/2
D)=(3/4)^1/2

Answer 1

Answer:

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