Question

radical form 32 1/6 is​

Answer 1

Given:

32^(1/6)

To Find:

Convert to Radical form 32^(1/6)?

Solution:

here, given that- $32^{1/6}$

Since, we know that - If n is a positive integer that x and a is a real number or a factor, then $a^{x/n}=\sqrt[n]{a^x}$

now, using this rule to convert  $32^{1/6}$ to a radical, where a=32, x=1 and n=6

$\sqrt[6]{32}$

Hence,

Exact form:

$\sqrt[6]{32}$

Decimal Form:

2

Answer 2

Step-by-step explanation:

Given Radical form of 32^1/6 is

• So we have 32^1/6  
• We need to write this in radical form.
• So if the positive integer is n which is greater than x and a is a real number or a factor, then  
• We have a^x/n = nth root of a^x
• So a^x/n = nth root of a^x
• So we need to convert 32^1/6 to radical form where a = 32, x = 1 and n = 6
• So we get 6th root of 32  =

Reference link will be

https://brainly.in/question/26089748