Radius and height of the right circular cylinder are same and total surface area of a cylinder is616 sq.cm then find
1) radius
2) base area
3) curved surface area
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(1) TSA of cylinder = 2πr(r+h)
616 = 2*22/7*r(r+r)
616 = 2*22/7*r(2r)
616 = 2*22/7*2r²
616*7/2*22 = 2r²
539 = 2r²
539/2 = r²
269.5 = r²
√269.5 = r
16.41 = r
r = 16.41cm
h = 16.41 cm
(3) CSA of cylinder = 2πrh
=2*22/7*16.41*16.41
=1692.66 cm²
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616 = 2*22/7*r(r+r)
616 = 2*22/7*r(2r)
616 = 2*22/7*2r²
616*7/2*22 = 2r²
539 = 2r²
539/2 = r²
269.5 = r²
√269.5 = r
16.41 = r
r = 16.41cm
h = 16.41 cm
(3) CSA of cylinder = 2πrh
=2*22/7*16.41*16.41
=1692.66 cm²
hope it will help you....
please mark as brainlist and follow me
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