Radius of a capillary is 2×10−3m. A liquid of weight 6.28×10−4n may remain in the capillary. Then the surface tension of liquid will be
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Answer:
5*10^-2 N/m
Explanation:
Since, Force = T×2πR
So,
6.28×10
−4
=T×2πR
T=
2×π×2×10
−3
6.28×10
−4
T=5×10
−2
N/m
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