Question

radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord?​

Answer 1

Answer:

49.34 cm is the required length of the chord .

According to the Question

It is given that ,

Radius of circle OA = 25cm

Distance of its Chord from the centre ,BO =4cm

we need to calculate the length of the Chord.

So ,We will use here the Pythagoras Theorem .

AO² = BO² + AB²

Substitute the value we get

➻ 25² = 4² + AB²

➻ 625 = 16 + AB²

➻ 625-16 = AB²

➻ 609 = AB²

➻ AB = √609

➻ AB = 24.67cm

As we know that distance of its Chord from the the centre is perpendicular bisector of the chord .

So, the length of the chord is twice AB

➻ Length of Chord = 2AB

➻ Length of Chord = 2×24.67

➻ Length of Chord = 49.34 cm

Hence, the length of the chord is 49.34 cm (approx)

Answer 2

Hope this will help you...