radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord?
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49.34 cm is the required length of the chord.
Step-by-step explanation:
According to the Question
It is given that,
Radius of circle OA = 25cm
Distance of its Chord from the centre ,BO = 4cm
we need to calculate the length of the Chord. So,We will use here the Pythagoras Theorem.
AO² BO² + AB²
Substitute the value we get
25² 4² + AB²
625 = 16+ AB²
625-16 AB²
609AB²
AB= √609
AB= 24.67cm
As we know that distance of its Chord from the the centre is perpendicular bisector of the chord.
So, the length of the chord is twice AB
Length of Chord = 2AB
Length of Chord = 2×24.67
Length of Chord = 49.34 cm
Hence, the length of the chord is 49.34 cm (approx)
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