Question

Radius of a circle is 34 cm and
the distance of the chord from
the centre is 30 cm, find the
length of the chord.​

Answer 1

Answer:

32 cm

Step-by-step explanation:

Answer 2

See the attachment $\Large\Uparrow \Uparrow \Uparrow \Uparrow$

$\huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}$$\huge \Rightarrow$

$\Large \bold \red{Solution}\Rightarrow$

Let the centre of the circle be O, seg AB be the given chord and seg OM $\large \bot$ chord AB such that A - M - B

OA = 34 cm , OM = 30 cm

In right angled $\triangle OMA$,

by Pythagoras' theorem,

$\large \Rightarrow$OA² = OM² + AM²

$\large \Rightarrow$34² = 30² + AM²

$\large \Rightarrow$1156 = 900 + AM²

$\large \Rightarrow$AM² = 1156 - 900

$\large \Rightarrow$AM² = 256

$\large \Rightarrow$AM = $\sqrt {256}$

$\large \Rightarrow$AM = 16 cm

Now , the Perpendicular drawn from the centre of the circle to the chord of the circle bisects the chord.

$\large \Rightarrow AM= \frac {1}{2}$

$\large \Rightarrow 16 = \frac {1}{2}$

$\large \Rightarrow AB = 16×2$

$\large \Rightarrow AB=32cm$

$\Large \bold\blue {Ans}\Longrightarrow$