radius of a circle with centre O is 41 units . length of a chord pQ is 80 units,find the distance of the chord from the centre of the circle
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OP=41 units
PQ=80 units
PR= RQ= 40 units
{OR perpendicular to PQ}
OPR is a right angled triangle, 90° at R.
So, by Pythagoras Theorem
(41)²=(40)²+OR²
OR²=1681-1600
OR²=81
OR=9 units
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