Math, asked by shwetakush07, 5 months ago

radius of a solid cylinder is 23 cm and the height is 26 cm. if three hemispheres of radius 35 cm are removed from each base of the cylin then what will be the total surface area of the remaining solid​

Answers

Answered by wankhadesonalika
0

Answer:

41734

Step-by-step explanation:

total surface area of cylinder = 2πr(r+h)

2×22/7×23 ×(23+27)

2×22/7 ×23 ×49

2×22×23×7

7084

total surface area of hemisphere = 3πr^2

3×22/7× 35×35

3×22×175

11550

their are 3 hemisphere = 3× 11550

34650

area of solid figure = area of cylinder + area of hemisphere

7084 + 34650

41734

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