radius of an iron sphere is 0.21 centimetre. If density of iron is 7.80 clcc calculate its mass
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Radius = r = 0.21cm
Density = 7.80 g/ cm³
Volume of a sphere = 4/3πr³
= 4/3 × 22/7 × 0.21 × 0.21 × 0.21
= 0.38808 cm ³
Density = Mass ÷ Volume
Mass = Density × Volume
= 7.80 × 0.38808
= 3.02 grams [ approx.]
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Density = 7.80 g/ cm³
Volume of a sphere = 4/3πr³
= 4/3 × 22/7 × 0.21 × 0.21 × 0.21
= 0.38808 cm ³
Density = Mass ÷ Volume
Mass = Density × Volume
= 7.80 × 0.38808
= 3.02 grams [ approx.]
Read more on Brainly.in - https://brainly.in/question/1150013#readmore
rahul1168:
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Answered by
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Radius of iron sphere , r = 0.21 cm;
Density of iron is, d = 7.80g/cc
Mass of the iron sphere, m = ?
Mass = Volume * Density
M =
4
3
πr
3
* 7.80
M =
4
3
*
22
7
*
(0.21)
3
* 7.80
M = 0.303 g
Density of iron is, d = 7.80g/cc
Mass of the iron sphere, m = ?
Mass = Volume * Density
M =
4
3
πr
3
* 7.80
M =
4
3
*
22
7
*
(0.21)
3
* 7.80
M = 0.303 g
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