radius of an iron sphere is 0.21 cm . if density of iron is 7.80 g / cc, calculate its mass
Answers
Answered by
135
Volume of the Sphere is 4/3πr^3
So, Volume = 4/3 × 22/7 × (.21)^3 or, .0388 cm^3
Mass = Density × Volume
So, The answer = 7.8 × .0388 or, .3026 g
Now you got the answer:))
So, Volume = 4/3 × 22/7 × (.21)^3 or, .0388 cm^3
Mass = Density × Volume
So, The answer = 7.8 × .0388 or, .3026 g
Now you got the answer:))
Answered by
125
Hi there !!
Radius = r = 0.21cm
Density = 7.80 g/ cm³
Volume of a sphere = 4/3πr³
= 4/3 × 22/7 × 0.21 × 0.21 × 0.21
= 0.38808 cm ³
Density = Mass ÷ Volume
Mass = Density × Volume
= 7.80 × 0.38808
= 3.02 grams [ approx.]
Radius = r = 0.21cm
Density = 7.80 g/ cm³
Volume of a sphere = 4/3πr³
= 4/3 × 22/7 × 0.21 × 0.21 × 0.21
= 0.38808 cm ³
Density = Mass ÷ Volume
Mass = Density × Volume
= 7.80 × 0.38808
= 3.02 grams [ approx.]
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