radius of circle is 10cm length of one chord is 12cm find its chord from the center
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adityamarzara7824:
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hey there
construct a perpendicular from centre of circle to chord (OM)
radius of circle =10 cm(OA)
length of chord =12cm(AB)
the perpendicular drawn from centre of centre to the chord bisects the chord
therefore length of AM is 12/2=6
By pythagorous theorem
OM^2+ AM^2= OA^2
om^2+6^2=10^2
om^2+36=100
om^2=100-36
om^2= 64
om= √64
= 8
there the distance between chord and centre of circle is 8cm
hope this helps!!!!
construct a perpendicular from centre of circle to chord (OM)
radius of circle =10 cm(OA)
length of chord =12cm(AB)
the perpendicular drawn from centre of centre to the chord bisects the chord
therefore length of AM is 12/2=6
By pythagorous theorem
OM^2+ AM^2= OA^2
om^2+6^2=10^2
om^2+36=100
om^2=100-36
om^2= 64
om= √64
= 8
there the distance between chord and centre of circle is 8cm
hope this helps!!!!
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