Radius of circle is 13cm and one of it chord is 10cm thn distanceof chord from centre
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be the mid point of AB, So
AP = PB
OP = 12 cm = distance of chord from center
And
AO = 13 cm = Radius
Now, OPA forms a right angle triangle.
Now, by pythagorous theorem,
AO2 = OP2 + AP2
AP2 = AO2 - OP2
AP2 = 132 - 122
AP2 = 169 - 144
AP2 = 25
AP = 5 cm.
Now,
AB = AP + PB = AP + AP = 5 +5 = 10 cm.
AP = PB
OP = 12 cm = distance of chord from center
And
AO = 13 cm = Radius
Now, OPA forms a right angle triangle.
Now, by pythagorous theorem,
AO2 = OP2 + AP2
AP2 = AO2 - OP2
AP2 = 132 - 122
AP2 = 169 - 144
AP2 = 25
AP = 5 cm.
Now,
AB = AP + PB = AP + AP = 5 +5 = 10 cm.
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