Question

radius of curvature of a convex mirror used on a moving automobile 2 metre.a truck is coming behind it at a constant distance of 3m. calculate the position size nature of the image formed.​

Answer 1

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${R=2m}$

$F=\frac{R}{2}={1m}$

${u= -3m}$

we know that,

$\frac{2}{R}=\frac{1}{v}+\frac{1}{u}$

➪$\frac{2}{2}=\frac{1}{v}-\frac{1}{3}$

➪$\frac{1}{v}=1+\frac{1}{3}=\frac{4}{3}$

➪${V=0.75}$

The image is at a distance ${0.75}$ m from the mirror on the side opposite to the object.

Size of the image is = $\frac{-v}{u} =\frac{-0.75}{(-3)} = {0.25}$

The size of the image is${0.25}$ times the object. The image is virtual, diminished and erect.

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Answer 2

Answer:

* position = 0.75 m from the mirror.

* nature - virtual, erect and diminished