Question

Radius of curvature of one surface of double convex lens is three times of the other. If focal length of the lens is 30 cm and refractive index of the lens is 3/2, then radius of curvature of that surface is​

Answer 1

Explanation:

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Answer 2

Concept Introduction: Mirror and lenses are basics for physics.

Given:

We have been Given: Focal length

$30cm$

refractive index

$\frac{3}{2}$

To Find:

We have to Find: the radius of curvature of that surface is?

Solution:

According to the problem, By Lens Maker's Formula we get,

$\frac{1}{f} = (n - 1)( \frac{1}{r1} - \frac{1}{r2} ) \\ \frac{1}{30} = ( \frac{3}{2} - 1)( \frac{1}{r} + \frac{1}{3r} ) \\ \frac{1}{30} = \frac{2}{3r} \\ r = \frac{2 \times 30}{3} \\ r = 20cm$

Final Answer: The Radius of Curvature is

$20cm$

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